If we are too draw another green marble the same probability 6 15 will be resulted.
There are 9 red and 6 green marbles.
So i could pick that red marble or that red marble.
The total number of marbles in the box is 25 that is 9 green 5 blue and 11 red.
There s two green marbles in the bag.
There are 9 red and 6 green marbles in a bag if a child reaches the bag randomly and picks 6.
Be careful letting children play with marbles they may swallow.
You wish to know t probability that the single chosen green or blue marble.
There are a total of 14 green and blue marbles so the probability is 14 25 or 56.
In the bag there are 6 green marbles and 12 red marbles.
So this is all the possible outcomes.
As both requirements have to be fulfilled the required probability is the multiplication of both 6 15 6 15.
There s two red marbles in the bag.
9 blue marbles 8 green marbles 4 red marbles 8 white marbles and 6 yellow marbles.
What percent of the marbles aren t blue.
In a jar of red green and blue marbles all but 6 are red marbles all but 8 are green and all but 4 are blue.
What is the probability of that child getting a green marble.
So i could pick that green marble or that green marble.
What is the probability of drawing a green marble from the bag.
There are 35 marbles in a bag.
There are still 6 green marbles and 9 red ones.
And then there s one blue marble in the bag.
At this moment the bag becomes the same as it is before a green marble is drawn i e.
Finally multiply the probabilities and reduce to get 3 95 share.
4 20 then find the probability of picking green again 3 19.
There are 6 red 4 green 5 blue and 5 yellow marbles in a jar.
Jun 21 2018 1 3 explanation.
A child reaches in the bag and randomly takes one marble.
These are clearly all yellow.
1 answer jim g.
Remember there is one less marble in the jar and that you assume the marble picked was green.
There are 9 red and 6 green marbles in a bag.
Solution from the condition we can determine how many marbles of each color were there in the jar.
7 red 5 green 6 blue pick 7 6 1 14 marbles and at least 1 is red because 14 green blue 11 at least 1 is blue because 14 red green 12 at least 1 is green because 14 red blue 13 picking 13 marbles could result in green marble absence if all 13 marbl.
Indeed we have these equations where r is the number of red marbles g is the number.